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0=-0.04x+0.00018x^2
We move all terms to the left:
0-(-0.04x+0.00018x^2)=0
We add all the numbers together, and all the variables
-(-0.04x+0.00018x^2)=0
We get rid of parentheses
-0.00018x^2+0.04x=0
a = -0.00018; b = 0.04; c = 0;
Δ = b2-4ac
Δ = 0.042-4·(-0.00018)·0
Δ = 0.0016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.04)-\sqrt{0.0016}}{2*-0.00018}=\frac{-0.04-\sqrt{0.0016}}{-0.00036} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.04)+\sqrt{0.0016}}{2*-0.00018}=\frac{-0.04+\sqrt{0.0016}}{-0.00036} $
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